7b-3(b+1)=2(3b+1)

Solution for 7b-3(b+1)=2(3b+1) equation:

Simplifying
7b + -3(b + 1) = 2(3b + 1)

Reorder the terms:
7b + -3(1 + b) = 2(3b + 1)
7b + (1 * -3 + b * -3) = 2(3b + 1)
7b + (-3 + -3b) = 2(3b + 1)

Reorder the terms:
-3 + 7b + -3b = 2(3b + 1)

Combine like terms: 7b + -3b = 4b
-3 + 4b = 2(3b + 1)

Reorder the terms:
-3 + 4b = 2(1 + 3b)
-3 + 4b = (1 * 2 + 3b * 2)
-3 + 4b = (2 + 6b)

Solving
-3 + 4b = 2 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
-3 + 4b + -6b = 2 + 6b + -6b

Combine like terms: 4b + -6b = -2b
-3 + -2b = 2 + 6b + -6b

Combine like terms: 6b + -6b = 0
-3 + -2b = 2 + 0
-3 + -2b = 2

Add '3' to each side of the equation.
-3 + 3 + -2b = 2 + 3

Combine like terms: -3 + 3 = 0
0 + -2b = 2 + 3
-2b = 2 + 3

Combine like terms: 2 + 3 = 5
-2b = 5

Divide each side by '-2'.
b = -2.5

Simplifying
b = -2.5