7b-2(b+2)=5(b-1)+1

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Solution for 7b-2(b+2)=5(b-1)+1 equation:


Simplifying
7b + -2(b + 2) = 5(b + -1) + 1

Reorder the terms:
7b + -2(2 + b) = 5(b + -1) + 1
7b + (2 * -2 + b * -2) = 5(b + -1) + 1
7b + (-4 + -2b) = 5(b + -1) + 1

Reorder the terms:
-4 + 7b + -2b = 5(b + -1) + 1

Combine like terms: 7b + -2b = 5b
-4 + 5b = 5(b + -1) + 1

Reorder the terms:
-4 + 5b = 5(-1 + b) + 1
-4 + 5b = (-1 * 5 + b * 5) + 1
-4 + 5b = (-5 + 5b) + 1

Reorder the terms:
-4 + 5b = -5 + 1 + 5b

Combine like terms: -5 + 1 = -4
-4 + 5b = -4 + 5b

Add '4' to each side of the equation.
-4 + 4 + 5b = -4 + 4 + 5b

Combine like terms: -4 + 4 = 0
0 + 5b = -4 + 4 + 5b
5b = -4 + 4 + 5b

Combine like terms: -4 + 4 = 0
5b = 0 + 5b
5b = 5b

Add '-5b' to each side of the equation.
5b + -5b = 5b + -5b

Combine like terms: 5b + -5b = 0
0 = 5b + -5b

Combine like terms: 5b + -5b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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