7b-2(3b-4)-3b=3(b-1)+4

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Solution for 7b-2(3b-4)-3b=3(b-1)+4 equation: 



7b-2(3b-4)-3b=3(b-1)+4

We move all terms to the left:

7b-2(3b-4)-3b-(3(b-1)+4)=0

We add all the numbers together, and all the variables

4b-2(3b-4)-(3(b-1)+4)=0

We multiply parentheses

4b-6b-(3(b-1)+4)+8=0



We calculate terms in parentheses: -(3(b-1)+4), so:

3(b-1)+4

We multiply parentheses

3b-3+4

We add all the numbers together, and all the variables

3b+1

Back to the equation:

-(3b+1)



We add all the numbers together, and all the variables

-2b-(3b+1)+8=0

We get rid of parentheses

-2b-3b-1+8=0

We add all the numbers together, and all the variables

-5b+7=0

We move all terms containing b to the left, all other terms to the right

-5b=-7

b=-7/-5

b=1+2/5

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