7b-1=5(b+3)

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Solution for 7b-1=5(b+3) equation: 



7b-1=5(b+3)

We move all terms to the left:

7b-1-(5(b+3))=0



We calculate terms in parentheses: -(5(b+3)), so:

5(b+3)

We multiply parentheses

5b+15

Back to the equation:

-(5b+15)



We get rid of parentheses

7b-5b-15-1=0

We add all the numbers together, and all the variables

2b-16=0

We move all terms containing b to the left, all other terms to the right

2b=16

b=16/2

b=8

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