7b+3-4b=3-3(b+4)=-2

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Solution for 7b+3-4b=3-3(b+4)=-2 equation: 



7b+3-4b=3-3(b+4)=-2

We move all terms to the left:

7b+3-4b-(3-3(b+4))=0

We add all the numbers together, and all the variables

3b-(3-3(b+4))+3=0



We calculate terms in parentheses: -(3-3(b+4)), so:

3-3(b+4)

determiningTheFunctionDomain
-3(b+4)+3

We multiply parentheses

-3b-12+3

We add all the numbers together, and all the variables

-3b-9

Back to the equation:

-(-3b-9)



We get rid of parentheses

3b+3b+9+3=0

We add all the numbers together, and all the variables

6b+12=0

We move all terms containing b to the left, all other terms to the right

6b=-12

b=-12/6

b=-2

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