7b+2-4b=2(b+4)

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Solution for 7b+2-4b=2(b+4) equation: 



7b+2-4b=2(b+4)

We move all terms to the left:

7b+2-4b-(2(b+4))=0

We add all the numbers together, and all the variables

3b-(2(b+4))+2=0



We calculate terms in parentheses: -(2(b+4)), so:

2(b+4)

We multiply parentheses

2b+8

Back to the equation:

-(2b+8)



We get rid of parentheses

3b-2b-8+2=0

We add all the numbers together, and all the variables

b-6=0

We move all terms containing b to the left, all other terms to the right

b=6

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