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7a(3a+5)=0
We multiply parentheses
21a^2+35a=0
a = 21; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·21·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*21}=\frac{-70}{42} =-1+2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*21}=\frac{0}{42} =0 $
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