7=3(y+4)-8y

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Solution for 7=3(y+4)-8y equation: 



7=3(y+4)-8y

We move all terms to the left:

7-(3(y+4)-8y)=0



We calculate terms in parentheses: -(3(y+4)-8y), so:

3(y+4)-8y

We add all the numbers together, and all the variables

-8y+3(y+4)

We multiply parentheses

-8y+3y+12

We add all the numbers together, and all the variables

-5y+12

Back to the equation:

-(-5y+12)



We get rid of parentheses

5y-12+7=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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