7=3(k+1)-2

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Solution for 7=3(k+1)-2 equation: 



7=3(k+1)-2

We move all terms to the left:

7-(3(k+1)-2)=0



We calculate terms in parentheses: -(3(k+1)-2), so:

3(k+1)-2

We multiply parentheses

3k+3-2

We add all the numbers together, and all the variables

3k+1

Back to the equation:

-(3k+1)



We get rid of parentheses

-3k-1+7=0

We add all the numbers together, and all the variables

-3k+6=0

We move all terms containing k to the left, all other terms to the right

-3k=-6

k=-6/-3

k=+2

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