7=2+5(z+2)

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Solution for 7=2+5(z+2) equation: 



7=2+5(z+2)

We move all terms to the left:

7-(2+5(z+2))=0



We calculate terms in parentheses: -(2+5(z+2)), so:

2+5(z+2)

determiningTheFunctionDomain
5(z+2)+2

We multiply parentheses

5z+10+2

We add all the numbers together, and all the variables

5z+12

Back to the equation:

-(5z+12)



We get rid of parentheses

-5z-12+7=0

We add all the numbers together, and all the variables

-5z-5=0

We move all terms containing z to the left, all other terms to the right

-5z=5

z=5/-5

z=-1

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