7=2(j+1)-13

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Solution for 7=2(j+1)-13 equation: 



7=2(j+1)-13

We move all terms to the left:

7-(2(j+1)-13)=0



We calculate terms in parentheses: -(2(j+1)-13), so:

2(j+1)-13

We multiply parentheses

2j+2-13

We add all the numbers together, and all the variables

2j-11

Back to the equation:

-(2j-11)



We get rid of parentheses

-2j+11+7=0

We add all the numbers together, and all the variables

-2j+18=0

We move all terms containing j to the left, all other terms to the right

-2j=-18

j=-18/-2

j=+9

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