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7=(x)(6x-1)
We move all terms to the left:
7-((x)(6x-1))=0
We calculate terms in parentheses: -(x(6x-1)), so:We get rid of parentheses
x(6x-1)
We multiply parentheses
6x^2-1x
Back to the equation:
-(6x^2-1x)
-6x^2+1x+7=0
We add all the numbers together, and all the variables
-6x^2+x+7=0
a = -6; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·(-6)·7
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-13}{2*-6}=\frac{-14}{-12} =1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+13}{2*-6}=\frac{12}{-12} =-1 $
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