7=(N-4)1/3

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Solution for 7=(N-4)1/3 equation: 


N in (-oo:+oo)

7 = ((N-4)^1)/3 // - ((N-4)^1)/3

7-(((N-4)^1)/3) = 0

7-((N-4)/3) = 0

(-1*(N-4))/3+7 = 0

(-1*(N-4))/3+(3*7)/3 = 0

3*7-1*(N-4) = 0

25-N = 0

(25-N)/3 = 0

(25-N)/3 = 0 // * 3

25-N = 0

25-N = 0 // - 25

-N = -25 // * -1

N = 25

N = 25

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