7=(3c-11)+-6c

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Solution for 7=(3c-11)+-6c equation:



7=(3c-11)+-6c
We move all terms to the left:
7-((3c-11)+-6c)=0
We use the square of the difference formula
-((3c-11)-6c)+7=0
We calculate terms in parentheses: -((3c-11)-6c), so:
(3c-11)-6c
We add all the numbers together, and all the variables
-6c+(3c-11)
We get rid of parentheses
-6c+3c-11
We add all the numbers together, and all the variables
-3c-11
Back to the equation:
-(-3c-11)
We get rid of parentheses
3c+11+7=0
We add all the numbers together, and all the variables
3c+18=0
We move all terms containing c to the left, all other terms to the right
3c=-18
c=-18/3
c=-6

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