7=(16/2x)+3

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Solution for 7=(16/2x)+3 equation: 



7=(16/2x)+3

We move all terms to the left:

7-((16/2x)+3)=0



Domain of the equation: 2x)+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+16/2x)+3)+7=0

We multiply all the terms by the denominator


-((+16+7*2x)+3)=0



We calculate terms in parentheses: -((+16+7*2x)+3), so:

(+16+7*2x)+3

We add all the numbers together, and all the variables

(7*2x+16)+3

We get rid of parentheses

7*2x+16+3

We add all the numbers together, and all the variables

7*2x+19

Wy multiply elements

14x+19

Back to the equation:

-(14x+19)



We get rid of parentheses

-14x-19=0

We move all terms containing x to the left, all other terms to the right

-14x=19

x=19/-14

x=-1+5/14

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