7=(1/3)(2f-12)

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Solution for 7=(1/3)(2f-12) equation: 


f in (-oo:+oo)

7 = (1/3)*(2*f-12) // - (1/3)*(2*f-12)

7-((1/3)*(2*f-12)) = 0

(-1/3)*(2*f-12)+7 = 0

7-1/3*(2*f-12) = 0

7-1/3*(2*f-12) = 0

11-2/3*f = 0

11-2/3*f = 0

11-2/3*f = 0 // - 11

-2/3*f = -11 // : -2/3

f = -11/(-2/3)

f = 33/2

f = 33/2

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