79-(3p+4)=-2(2p+1)+10

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Solution for 79-(3p+4)=-2(2p+1)+10 equation: 



79-(3p+4)=-2(2p+1)+10

We move all terms to the left:

79-(3p+4)-(-2(2p+1)+10)=0

We get rid of parentheses

-3p-(-2(2p+1)+10)-4+79=0



We calculate terms in parentheses: -(-2(2p+1)+10), so:

-2(2p+1)+10

We multiply parentheses

-4p-2+10

We add all the numbers together, and all the variables

-4p+8

Back to the equation:

-(-4p+8)



We add all the numbers together, and all the variables

-3p-(-4p+8)+75=0

We get rid of parentheses

-3p+4p-8+75=0

We add all the numbers together, and all the variables

p+67=0

We move all terms containing p to the left, all other terms to the right

p=-67

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