79+3*(3x-18)=4*(4x+16)-60

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Solution for 79+3*(3x-18)=4*(4x+16)-60 equation: 



79+3(3x-18)=4(4x+16)-60

We move all terms to the left:

79+3(3x-18)-(4(4x+16)-60)=0

We multiply parentheses

9x-(4(4x+16)-60)-54+79=0



We calculate terms in parentheses: -(4(4x+16)-60), so:

4(4x+16)-60

We multiply parentheses

16x+64-60

We add all the numbers together, and all the variables

16x+4

Back to the equation:

-(16x+4)



We add all the numbers together, and all the variables

9x-(16x+4)+25=0

We get rid of parentheses

9x-16x-4+25=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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