78=3(x+5)-3(4-4x)

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Solution for 78=3(x+5)-3(4-4x) equation: 



78=3(x+5)-3(4-4x)

We move all terms to the left:

78-(3(x+5)-3(4-4x))=0

We add all the numbers together, and all the variables

-(3(x+5)-3(-4x+4))+78=0



We calculate terms in parentheses: -(3(x+5)-3(-4x+4)), so:

3(x+5)-3(-4x+4)

We multiply parentheses

3x+12x+15-12

We add all the numbers together, and all the variables

15x+3

Back to the equation:

-(15x+3)



We get rid of parentheses

-15x-3+78=0

We add all the numbers together, and all the variables

-15x+75=0

We move all terms containing x to the left, all other terms to the right

-15x=-75

x=-75/-15

x=+5

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