77((x-2)x+3)-21=7+(7x-49)

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Solution for 77((x-2)x+3)-21=7+(7x-49) equation: 



77((x-2)x+3)-21=7+(7x-49)

We move all terms to the left:

77((x-2)x+3)-21-(7+(7x-49))=0



We calculate terms in parentheses: -(7+(7x-49)), so:

7+(7x-49)

determiningTheFunctionDomain
(7x-49)+7

We get rid of parentheses

7x-49+7

We add all the numbers together, and all the variables

7x-42

Back to the equation:

-(7x-42)



We get rid of parentheses

77((x-2)x+3)-7x+42-21=0

We add all the numbers together, and all the variables

-7x+77((x-2)x+3)+21=0

We move all terms containing x to the left, all other terms to the right

-7x+77((x-2)x+3)=-21

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