If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^5+4*x^3-(8*x^2)-32 = 0;x
x
(2*pi)/((-2*pi)/7)
(sin(x))^3+(cos(x))^3
2/(7/6)
10.38/2
| 2(x-2)-20=21-7x | | 5x^2-33xy+18y^2=0 | | 3z-z+4z= | | 19x^2-4=0 | | 7+3=37 | | 23-h=13 | | 6/k-4/k=3/5-3/k | | 16a^5-20a^3=4a^3(4a^2-5) | | C(R)=4R+12 | | X(3-x)(x+5)=0 | | 2(2w+9)=57 | | 2/(7/6) | | 20=-8u+6(u+2) | | 5(1.5+m)=71.25 | | ((3.14(d/2)^2)*.05) | | 15m^3-6m=3m(5m^2-6m) | | 9x+4y=-25 | | -6(2+4n)=-38+2n | | 6-4x=-2x+10 | | 3/7x48 | | x(x+2)(x+5)=14850 | | 5-.4(3x+2)=-(x-6) | | 3.6x=18 | | x=10e+8 | | 6m^2+18m=6m^2(1+3m) | | x(x-2)(x+3)=14850 | | 3(2x+9)-13=2(x+3) | | 5.3+u=3.2u-2.1 | | -8x+1=2x+12 | | x/3-y/4 | | L(t)=30sin(t)-20cos(t) | | 32m^4+12m^3=4m^3(8m+3) |