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75x+439.99x^2=1
We move all terms to the left:
75x+439.99x^2-(1)=0
a = 439.99; b = 75; c = -1;
Δ = b2-4ac
Δ = 752-4·439.99·(-1)
Δ = 7384.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{7384.96}}{2*439.99}=\frac{-75-\sqrt{7384.96}}{879.98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{7384.96}}{2*439.99}=\frac{-75+\sqrt{7384.96}}{879.98} $
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