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75.36=r2
We move all terms to the left:
75.36-(r2)=0
We add all the numbers together, and all the variables
-1r^2+75.36=0
a = -1; b = 0; c = +75.36;
Δ = b2-4ac
Δ = 02-4·(-1)·75.36
Δ = 301.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{301.44}}{2*-1}=\frac{0-\sqrt{301.44}}{-2} =-\frac{\sqrt{}}{-2} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{301.44}}{2*-1}=\frac{0+\sqrt{301.44}}{-2} =\frac{\sqrt{}}{-2} $
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