73y=36(2y+12)

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Solution for 73y=36(2y+12) equation: 



73y=36(2y+12)

We move all terms to the left:

73y-(36(2y+12))=0



We calculate terms in parentheses: -(36(2y+12)), so:

36(2y+12)

We multiply parentheses

72y+432

Back to the equation:

-(72y+432)



We get rid of parentheses

73y-72y-432=0

We add all the numbers together, and all the variables

y-432=0

We move all terms containing y to the left, all other terms to the right

y=432

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