73=9/5c+3

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Solution for 73=9/5c+3 equation: 



73=9/5c+3

We move all terms to the left:

73-(9/5c+3)=0



Domain of the equation: 5c+3)!=0

c∈R



We get rid of parentheses

-9/5c-3+73=0

We multiply all the terms by the denominator


-3*5c+73*5c-9=0

Wy multiply elements

-15c+365c-9=0

We add all the numbers together, and all the variables

350c-9=0

We move all terms containing c to the left, all other terms to the right

350c=9

c=9/350

c=9/350

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