73=3(2r+5)-2(r-5)

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Solution for 73=3(2r+5)-2(r-5) equation: 



73=3(2r+5)-2(r-5)

We move all terms to the left:

73-(3(2r+5)-2(r-5))=0



We calculate terms in parentheses: -(3(2r+5)-2(r-5)), so:

3(2r+5)-2(r-5)

We multiply parentheses

6r-2r+15+10

We add all the numbers together, and all the variables

4r+25

Back to the equation:

-(4r+25)



We get rid of parentheses

-4r-25+73=0

We add all the numbers together, and all the variables

-4r+48=0

We move all terms containing r to the left, all other terms to the right

-4r=-48

r=-48/-4

r=+12

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