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72m^2=10
We move all terms to the left:
72m^2-(10)=0
a = 72; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·72·(-10)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*72}=\frac{0-24\sqrt{5}}{144} =-\frac{24\sqrt{5}}{144} =-\frac{\sqrt{5}}{6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*72}=\frac{0+24\sqrt{5}}{144} =\frac{24\sqrt{5}}{144} =\frac{\sqrt{5}}{6} $
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