# 72=3u^2

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## Solution for 72=3u^2 equation:

72=3u^2
We move all terms to the left:
72-(3u^2)=0
a = -3; b = 0; c = +72;Δ = b2-4acΔ = 02-4·(-3)·72Δ = 864The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*-3}=\frac{0-12\sqrt{6}}{-6} =-\frac{12\sqrt{6}}{-6} =-\frac{2\sqrt{6}}{-1}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*-3}=\frac{0+12\sqrt{6}}{-6} =\frac{12\sqrt{6}}{-6} =\frac{2\sqrt{6}}{-1}$

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