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72=3u^2

We move all terms to the left:

72-(3u^2)=0

a = -3; b = 0; c = +72;

Δ = b^{2}-4ac

Δ = 0^{2}-4·(-3)·72

Δ = 864

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*-3}=\frac{0-12\sqrt{6}}{-6} =-\frac{12\sqrt{6}}{-6} =-\frac{2\sqrt{6}}{-1} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*-3}=\frac{0+12\sqrt{6}}{-6} =\frac{12\sqrt{6}}{-6} =\frac{2\sqrt{6}}{-1} $

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