72=3(4b+4)

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Solution for 72=3(4b+4) equation: 



72=3(4b+4)

We move all terms to the left:

72-(3(4b+4))=0



We calculate terms in parentheses: -(3(4b+4)), so:

3(4b+4)

We multiply parentheses

12b+12

Back to the equation:

-(12b+12)



We get rid of parentheses

-12b-12+72=0

We add all the numbers together, and all the variables

-12b+60=0

We move all terms containing b to the left, all other terms to the right

-12b=-60

b=-60/-12

b=+5

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