72=-3(m+4)+m

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Solution for 72=-3(m+4)+m equation: 



72=-3(m+4)+m

We move all terms to the left:

72-(-3(m+4)+m)=0



We calculate terms in parentheses: -(-3(m+4)+m), so:

-3(m+4)+m

We add all the numbers together, and all the variables

m-3(m+4)

We multiply parentheses

m-3m-12

We add all the numbers together, and all the variables

-2m-12

Back to the equation:

-(-2m-12)



We get rid of parentheses

2m+12+72=0

We add all the numbers together, and all the variables

2m+84=0

We move all terms containing m to the left, all other terms to the right

2m=-84

m=-84/2

m=-42

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