72=(-26+q)(3)

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Solution for 72=(-26+q)(3) equation: 



72=(-26+q)(3)

We move all terms to the left:

72-((-26+q)(3))=0

We add all the numbers together, and all the variables

-((q-26)3)+72=0



We calculate terms in parentheses: -((q-26)3), so:

(q-26)3

We multiply parentheses

3q-78

Back to the equation:

-(3q-78)



We get rid of parentheses

-3q+78+72=0

We add all the numbers together, and all the variables

-3q+150=0

We move all terms containing q to the left, all other terms to the right

-3q=-150

q=-150/-3

q=+50

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