70=3t+16t2

Solution for 70=3t+16t2 equation:

70=3t+16t^2

We move all terms to the left:

70-(3t+16t^2)=0

We get rid of parentheses

-16t^2-3t+70=0

a = -16; b = -3; c = +70;
Δ = b2-4ac
Δ = -32-4·(-16)·70
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-67}{2*-16}=\frac{-64}{-32}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+67}{2*-16}=\frac{70}{-32}
=-2+3/16
$