70=(2x-10)x

Solution for 70=(2x-10)x equation:

70=(2x-10)x

We move all terms to the left:

70-((2x-10)x)=0


We calculate terms in parentheses: -((2x-10)x), so:

(2x-10)x

We multiply parentheses

2x^2-10x

Back to the equation:

-(2x^2-10x)


We get rid of parentheses

-2x^2+10x+70=0

a = -2; b = 10; c = +70;
Δ = b2-4ac
Δ = 102-4·(-2)·70
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{165}}{2*-2}=\frac{-10-2\sqrt{165}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{165}}{2*-2}=\frac{-10+2\sqrt{165}}{-4}
$