70-4x=2(3x+2)-100

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Solution for 70-4x=2(3x+2)-100 equation: 



70-4x=2(3x+2)-100

We move all terms to the left:

70-4x-(2(3x+2)-100)=0



We calculate terms in parentheses: -(2(3x+2)-100), so:

2(3x+2)-100

We multiply parentheses

6x+4-100

We add all the numbers together, and all the variables

6x-96

Back to the equation:

-(6x-96)



We get rid of parentheses

-4x-6x+96+70=0

We add all the numbers together, and all the variables

-10x+166=0

We move all terms containing x to the left, all other terms to the right

-10x=-166

x=-166/-10

x=16+3/5

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