70(x+1)=99(2x-3)

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Solution for 70(x+1)=99(2x-3) equation: 



70(x+1)=99(2x-3)

We move all terms to the left:

70(x+1)-(99(2x-3))=0

We multiply parentheses

70x-(99(2x-3))+70=0



We calculate terms in parentheses: -(99(2x-3)), so:

99(2x-3)

We multiply parentheses

198x-297

Back to the equation:

-(198x-297)



We get rid of parentheses

70x-198x+297+70=0

We add all the numbers together, and all the variables

-128x+367=0

We move all terms containing x to the left, all other terms to the right

-128x=-367

x=-367/-128

x=2+111/128

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