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7/x+3=x-3
We move all terms to the left:
7/x+3-(x-3)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
7/x-x+3+3=0
We multiply all the terms by the denominator
-x*x+3*x+3*x+7=0
We add all the numbers together, and all the variables
6x-x*x+7=0
Wy multiply elements
-1x^2+6x+7=0
a = -1; b = 6; c = +7;
Δ = b2-4ac
Δ = 62-4·(-1)·7
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*-1}=\frac{-14}{-2} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*-1}=\frac{2}{-2} =-1 $
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