7/t=1/3-4/3t

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Solution for 7/t=1/3-4/3t equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

7/t = 1/3-((4/3)*t) // - 1/3-((4/3)*t)

(4/3)*t+7/t-(1/3) = 0

(4/3)*t+7/t-1/3 = 0

4/3*t^1+7*t^-1-1/3*t^0 = 0

(4/3*t^2-1/3*t^1+7*t^0)/(t^1) = 0 // * t^2

t^1*(4/3*t^2-1/3*t^1+7*t^0) = 0

t^1

(4/3)*t^2+(-1/3)*t+7 = 0

(4/3)*t^2+(-1/3)*t+7 = 0

DELTA = (-1/3)^2-(4*7*(4/3))

DELTA = -335/9

DELTA < 0

t in { } 

t belongs to the empty set

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