7/k-3/4-5k=3/8

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Solution for 7/k-3/4-5k=3/8 equation:


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

7/k-(5*k)-(3/4) = 3/8 // - 3/8

7/k-(5*k)-(3/4)-(3/8) = 0

7/k-5*k-3/4-3/8 = 0

7*k^-1-5*k^1-9/8*k^0 = 0

(7*k^0-5*k^2-9/8*k^1)/(k^1) = 0 // * k^2

k^1*(7*k^0-5*k^2-9/8*k^1) = 0

k^1

(-9/8)*k-5*k^2+7 = 0

(-9/8)*k-5*k^2+7 = 0

DELTA = (-9/8)^2-(-5*4*7)

DELTA = 9041/64

DELTA > 0

k = ((9041/64)^(1/2)-(-9/8))/(-5*2) or k = (-(-9/8)-(9041/64)^(1/2))/(-5*2)

k = ((9041/64)^(1/2)+9/8)/(-10) or k = (9/8-(9041/64)^(1/2))/(-10)

k in { ((9041/64)^(1/2)+9/8)/(-10), (9/8-(9041/64)^(1/2))/(-10)}

k in { ((9041/64)^(1/2)+9/8)/(-10), (9/8-(9041/64)^(1/2))/(-10) }

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