7/9b+42=105

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Solution for 7/9b+42=105 equation: 



7/9b+42=105

We move all terms to the left:

7/9b+42-(105)=0



Domain of the equation: 9b!=0

b!=0/9

b!=0

b∈R



We add all the numbers together, and all the variables

7/9b-63=0

We multiply all the terms by the denominator


-63*9b+7=0

Wy multiply elements

-567b+7=0

We move all terms containing b to the left, all other terms to the right

-567b=-7

b=-7/-567

b=1/81

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