7/8m-1/2=3/16m=5

Solution for 7/8m-1/2=3/16m=5 equation:

7/8m-1/2=3/16m=5

We move all terms to the left:

7/8m-1/2-(3/16m)=0


Domain of the equation: 8m!=0

m!=0/8

m!=0

m∈R



Domain of the equation: 16m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

7/8m-(+3/16m)-1/2=0

We get rid of parentheses

7/8m-3/16m-1/2=0

We calculate fractions


(-128m^2)/512m^2+448m/512m^2+(-96m)/512m^2=0

We multiply all the terms by the denominator


(-128m^2)+448m+(-96m)=0

We get rid of parentheses

-128m^2+448m-96m=0

We add all the numbers together, and all the variables

-128m^2+352m=0

a = -128; b = 352; c = 0;
Δ = b2-4ac
Δ = 3522-4·(-128)·0
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{123904}=352$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(352)-352}{2*-128}=\frac{-704}{-256}
=2+3/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(352)+352}{2*-128}=\frac{0}{-256}
=0
$