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7/7x+9=9/9x+5
We move all terms to the left:
7/7x+9-(9/9x+5)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 9x+5)!=0We get rid of parentheses
x∈R
7/7x-9/9x-5+9=0
We calculate fractions
63x/63x^2+(-63x)/63x^2-5+9=0
We add all the numbers together, and all the variables
63x/63x^2+(-63x)/63x^2+4=0
We multiply all the terms by the denominator
63x+(-63x)+4*63x^2=0
Wy multiply elements
252x^2+63x+(-63x)=0
We get rid of parentheses
252x^2+63x-63x=0
We add all the numbers together, and all the variables
252x^2=0
a = 252; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·252·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{504}=0$
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