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7/6x+2=7/2x
We move all terms to the left:
7/6x+2-(7/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/6x-(+7/2x)+2=0
We get rid of parentheses
7/6x-7/2x+2=0
We calculate fractions
14x/12x^2+(-42x)/12x^2+2=0
We multiply all the terms by the denominator
14x+(-42x)+2*12x^2=0
Wy multiply elements
24x^2+14x+(-42x)=0
We get rid of parentheses
24x^2+14x-42x=0
We add all the numbers together, and all the variables
24x^2-28x=0
a = 24; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·24·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*24}=\frac{56}{48} =1+1/6 $
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