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7/5x=x
We move all terms to the left:
7/5x-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+7/5x=0
We multiply all the terms by the denominator
-1x*5x+7=0
Wy multiply elements
-5x^2+7=0
a = -5; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-5)·7
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{35}}{2*-5}=\frac{0-2\sqrt{35}}{-10} =-\frac{2\sqrt{35}}{-10} =-\frac{\sqrt{35}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{35}}{2*-5}=\frac{0+2\sqrt{35}}{-10} =\frac{2\sqrt{35}}{-10} =\frac{\sqrt{35}}{-5} $
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