7/5(5z-4)=4/5z-5

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Solution for 7/5(5z-4)=4/5z-5 equation: 



7/5(5z-4)=4/5z-5

We move all terms to the left:

7/5(5z-4)-(4/5z-5)=0



Domain of the equation: 5(5z-4)!=0

z∈R





Domain of the equation: 5z-5)!=0

z∈R



We get rid of parentheses

7/5(5z-4)-4/5z+5=0

We calculate fractions


35z/(125z^2-100z)+(-20z5/(125z^2-100z)+5=0

We calculate fractions

We do not support ezpression: z^3

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