7/4y=35

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Solution for 7/4y=35 equation: 



7/4y=35

We move all terms to the left:

7/4y-(35)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We multiply all the terms by the denominator


-35*4y+7=0

Wy multiply elements

-140y+7=0

We move all terms containing y to the left, all other terms to the right

-140y=-7

y=-7/-140

y=1/20

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