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7/3y+y=180
We move all terms to the left:
7/3y+y-(180)=0
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
y+7/3y-180=0
We multiply all the terms by the denominator
y*3y-180*3y+7=0
Wy multiply elements
3y^2-540y+7=0
a = 3; b = -540; c = +7;
Δ = b2-4ac
Δ = -5402-4·3·7
Δ = 291516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291516}=\sqrt{4*72879}=\sqrt{4}*\sqrt{72879}=2\sqrt{72879}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-2\sqrt{72879}}{2*3}=\frac{540-2\sqrt{72879}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+2\sqrt{72879}}{2*3}=\frac{540+2\sqrt{72879}}{6} $
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