7/3x=5/x+6

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Solution for 7/3x=5/x+6 equation:



7/3x=5/x+6
We move all terms to the left:
7/3x-(5/x+6)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+6)!=0
x∈R
We get rid of parentheses
7/3x-5/x-6=0
We calculate fractions
7x/3x^2+(-15x)/3x^2-6=0
We multiply all the terms by the denominator
7x+(-15x)-6*3x^2=0
Wy multiply elements
-18x^2+7x+(-15x)=0
We get rid of parentheses
-18x^2+7x-15x=0
We add all the numbers together, and all the variables
-18x^2-8x=0
a = -18; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-18)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-18}=\frac{0}{-36} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-18}=\frac{16}{-36} =-4/9 $

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