7/3(2x-1)=1/5x+2/5(4-3x)

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Solution for 7/3(2x-1)=1/5x+2/5(4-3x) equation: 


x in (-oo:+oo)

(7/3)*(2*x-1) = (2/5)*(4-(3*x))+(1/5)*x // - (2/5)*(4-(3*x))+(1/5)*x

(7/3)*(2*x-1)-((2/5)*(4-(3*x)))-((1/5)*x) = 0

(7/3)*(2*x-1)+(-2/5)*(4-3*x)+(-1/5)*x = 0

7/3*(2*x-1)-2/5*(4-3*x)-x/5 = 0

(7/3*5*(2*x-1))/5+(-2/5*5*(4-3*x))/5-x/5 = 0

7/3*5*(2*x-1)-2/5*5*(4-3*x)-x = 0

88/3*x-x-59/3 = 0

85/3*x-59/3 = 0

(85/3*x-59/3)/5 = 0

(85/3*x-59/3)/5 = 0 // * 5

85/3*x-59/3 = 0

85/3*x-59/3 = 0 // + 59/3

85/3*x = 59/3 // : 85/3

x = 59/3/85/3

x = 59/85

x = 59/85

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