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7/2x-8=3/x-6
We move all terms to the left:
7/2x-8-(3/x-6)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x-6)!=0We get rid of parentheses
x∈R
7/2x-3/x+6-8=0
We calculate fractions
7x/2x^2+(-6x)/2x^2+6-8=0
We add all the numbers together, and all the variables
7x/2x^2+(-6x)/2x^2-2=0
We multiply all the terms by the denominator
7x+(-6x)-2*2x^2=0
Wy multiply elements
-4x^2+7x+(-6x)=0
We get rid of parentheses
-4x^2+7x-6x=0
We add all the numbers together, and all the variables
-4x^2+x=0
a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8} =0 $
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