7/2u-6=-2/u-3

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Solution for 7/2u-6=-2/u-3 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(7/2)*u-6 = -2/u-3 // + -2/u-3

(7/2)*u-(-2/u)-6+3 = 0

(7/2)*u+2*u^-1-6+3 = 0

7/2*u^1+2*u^-1-3*u^0 = 0

(7/2*u^2-3*u^1+2*u^0)/(u^1) = 0 // * u^2

u^1*(7/2*u^2-3*u^1+2*u^0) = 0

u^1

(7/2)*u^2-3*u+2 = 0

(7/2)*u^2-3*u+2 = 0

DELTA = (-3)^2-(2*4*(7/2))

DELTA = -19

DELTA < 0

u in { } 

u belongs to the empty set

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